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Given y^2 = tan x, what is dy/dx
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It is given that `y^2 = tan x` . To determine `dy/dx` use implicit differentiation.
`y^2 = tan x`
`(d(y^2))/dx = (d(tan x))/dx`
=> `2*y*(dy/dx) = sec^2x`
=> `dy/dx = (sec^2x)/(2*y)`
=> `dy/dx = (sec^2x)/(2*sqrt(tan x))`
The required derivative `dy/dx = (sec^2x)/(2*sqrt(tan x))`
Posted by justaguide on June 27, 2013 at 5:04 PM (Answer #1)
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