1 Answer | Add Yours
Let the length of the third side (i.e. BC) of the triangle be a.
Applying cosine rule for triangles, `cosA = (b^2+c^2-a^2)/(2bc)` ,
`rArra^2 = b^2+c^2-2b*c*cosA` ,
Putting the values from the given triangle, we get
`a^2 = 7^2+(4sqrt2)^2-2*7*4sqrt2*cos45°`
Therefore `a = sqrt25 = 5` units.
The length of the third side (i.e. BC) of the given triangle is 5 units.
We’ve answered 288,143 questions. We can answer yours, too.Ask a question