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Given that y varies inversely as x^2, and that y=16 when x=3, what is the value of y...
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If y is inversely proportional to `x^(2)` then we know that
y (is proportional to) `1/(x^2)`
Since we are given a value for x and y, we can find the value for the numerator so that we are no longer looking at a proportionality but an equation
Now, we can plug in the known values
`16 = z/(3^2)`
`16 = z/9`
z = 16*9
z = 144
Now that we know the value of z, we can use the same equation to solve for the unknown value of y
`y = 9`
Posted by mlsiasebs on April 10, 2012 at 5:32 PM (Answer #1)
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