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Given that v0=20 m/s and a=3 m/s^2 determine x for t = 10 s
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We are given that the initial velocity V0 = 20 m/s. The acceleration is given as 3 m/s^2.
Now we have to determine the distance travelled in 10s.
We first find the velocity after 10 s. As velocity changes by 3 m/s each second, in 10 s it changes by 3*10 = 30 m/s. So the final velocity is 50 m/s.
Therefore the distance travelled is equal to (20 + 50)*10/2 = 70*5 = 350 m
Therefore the distance moved is 350m.
Posted by william1941 on October 26, 2010 at 2:43 AM (Answer #1)
We'll have to write the equation that describes how far an object travels under constant acceleration.
x = v0t + at^2/2 (1)
To determine x, we'll insert all given information into equation:
x = (20m/s)(10s) + (1/2)(3m/s^2)(10s)^2
We'll cancel out the seconds from the first ratio and the s^2 from the second ratio from the right side and we'll get:
x = 200m + 150m
x = 350m
Keeping track of the units in calculus is helping us to detect the errors if the units don't come out right.
Posted by giorgiana1976 on October 26, 2010 at 2:23 AM (Answer #2)
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