- Download PDF
2 Answers | Add Yours
We are given that the initial velocity V0 = 20 m/s. The acceleration is given as 3 m/s^2.
Now we have to determine the distance travelled in 10s.
We first find the velocity after 10 s. As velocity changes by 3 m/s each second, in 10 s it changes by 3*10 = 30 m/s. So the final velocity is 50 m/s.
Therefore the distance travelled is equal to (20 + 50)*10/2 = 70*5 = 350 m
Therefore the distance moved is 350m.
We'll have to write the equation that describes how far an object travels under constant acceleration.
x = v0t + at^2/2 (1)
To determine x, we'll insert all given information into equation:
x = (20m/s)(10s) + (1/2)(3m/s^2)(10s)^2
We'll cancel out the seconds from the first ratio and the s^2 from the second ratio from the right side and we'll get:
x = 200m + 150m
x = 350m
Keeping track of the units in calculus is helping us to detect the errors if the units don't come out right.
We’ve answered 320,454 questions. We can answer yours, too.Ask a question