Given a muriatic acid with a concentration of 11.7 M, how many mL of the muriatic acid solution in 9.55g of hydrochloric acid.
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Molarity of HCl (M) = 11.7 M
Volume of HCl (V) = ? ml
Mass of HCl (m) = 9.55 g
Molar mass of HCl = 36.46 `(g)/(mol)`
`Molarity = ((mass)/(molar mass))*(1000/V)`
`11.7 = (9.55/36.46)*(1000/V)`
`V = (9.55*1000)/(11.7*36.46)`
`V = 9550/426.528`
V = 22.39 ml
Molarity = moles / volume in litres
Moles = mass/molar mass
Moles = `9.55/36.46`
Moles = 0.2619
11.7 = 0.2619/Volume
Volume = `0.2619/11.7`
Volume = 0.02238 litres = 22.38 ml.
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