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Given `lim_(x->6) f(x)=3` and `lim_(x->6) g(x)=7` , evaluate `lim_(x->6)...
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High School Teacher
Limit and continous function are commutative, that is if `c` is continous at `x_0` then `lim_(x->x_0) c(f(x))=c(lim_(x->x_0) f(x))`. Now since square root is continous at 6 it follows that
`lim_(x->6)sqrt(f(x)) = sqrt(lim_(x->6)f(x)) = sqrt(3)`
Posted by tiburtius on January 20, 2013 at 3:47 PM (Answer #1)
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