Given h(x)=2/x+1 find h^-1 and find the domain and range



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Posted on (Answer #1)


To find the inverse function we set it equal to y and solve for x.


Hence the inverse function is `h^(-1)(x)=[2-x]/x`

Domain: The new function is not defined for x=0, thus the domain is D=`(-oo,0)U(0,oo)`


Range: Since h(x) is not defined for x=-1, then -1 can't be an element of the range of `h^(-1)(x)`


The following graph of the inverse function confirm our findings.

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