# Given the function h(x)=x+5, what is h(0), h(-2), h(-19), h(9) and h(b+7)

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It is given that h(x)=x+5, The value of:

h(0) = 0 + 5 = 5

h(-2) = -2 + 5 = 3

h(-19) = -19 + 5 = -14

h(9) = 9 + 5 = 14

h(b+7) = b + 7 + 5 = b + 12

**The required values are: h(0) = 5, h(-2) = 3, h(-19) = -14, h(9) = 14 and h(b+7) = b + 12**

You must substitute x by the value which is specified in the brackets.

1) h(0)=0+5=5

2) h(-2)=-2+5=3

3) h(-19)=-19+5=-14 (the sign belongs to the bigger number)

4) h(9)=9+5=14

5) h(b+7)=(b+7)+5=b+12