1 Answer | Add Yours
In the following work we will be dealing with complex fractions, I will be simplifying the problem by multiplying by the LCD.
`f(g(x))=f([2x-4]/x)=[(2x-4)/x]/[(2x-4)/x-1]=` (Multiply the top and bottom by x)
`[2x-4]/[(2x-4)-x]=[2x-4]/[x-4]` This function is defined as long as x is not 4.
Thus domain is `(-oo,4)U(4,+oo)`
`g(f(x))=g(x/(x-1))=[2(x/(x-1))-4]/(x/(x-1))=` (Multiply top and bottom by x-1)
`f(f(x))=f(x/(x-1))=[x/(x-1)]/[x/(x-1)-1]=` (Multiply numerator and denominator by x-1)
We’ve answered 397,046 questions. We can answer yours, too.Ask a question