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Given the equation x^2 + (y-3)^2 = 25 a) What is the Center C?b) What is the length of...

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kristenmarieb... | Student, Grade 10 | (Level 1) Valedictorian

Posted June 27, 2013 at 4:24 AM via web

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Given the equation x^2 + (y-3)^2 = 25

a) What is the Center C?
b) What is the length of the radius r? 

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llltkl | College Teacher | (Level 3) Valedictorian

Posted June 27, 2013 at 4:38 AM (Answer #1)

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The standard form of the equation of a circle is: `(x-h)^2+(y-k)^2` , where the center C is (h,k) and the radius is r.

Here, the given equation is `x^2 + (y-3)^2 = 25` . We can rewrite this equation as:

`(x-0)^2+(y-3)^2=(5)^2`

Therefore, a) the center C is (0,3)

                 b) the length of the radius r is 5 units.

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