Given the equation 2x^2 - 50y^2 = 50, determine

a) The Center C

b) The 2 Vertices

c) The slopes of the asymptotes

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Given equation

`2x^2-50y^2=50`

rewrite equation as

`(2x^2)/50-(50y^2)/50=1`

`x^2/25-y^2/1=1`

So we have now equation of hyperbola in standard form .Thus

a. centre =(0,0)

b. vertices = `(+-5,0)`

c. Asymptotes

`(x/5-y)=0`

`(x/5+y)=0`

Thus

`y=+-(1/5)x`

So slopes are `+-(1/5)`

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