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Given:C(x,y)=2x^2+3y^2+2xy-6x-18y+54 Find a) Cx(x,y) and Cy(x,y) b)xand y such that...
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(Level 1) Associate Educator, Expert, Newton
To find `C_x` , treat x as a variable and y as a constant, and find the derivative:
x is the variable, then the derivative of `2x^2` is `4x`
if y is a constant, then `y^2` is a constant, and `3y^2 is a constant, so the derivative of `3y^2` is 0
`2xy` is really the variable `x` times the constant `2y`; the derivative of a constant times the variable is the constant, so the derivative is `2y`
similarly, the derivative of `-6x` is -6, the derivative of `-18y` is 0, and the derivative of 54 is 0.
`C_x(x,y) = 4x+0+2y-6-0+0=4x+2y-6`
To find `C_y`, treat y as the variable and x as a constant, and find the derivative:
Now, x is a constant, so `2x^2` is a constant, and the derivative is 0
The derivative of `3y^2` is `6y`
`2xy` is the variable `y` times the constant `2x` so the derivative is `2x`
x is a constant, so `-6x` is a constant, and its derivative is 0
the derivative of `-18y` is -18, and the derivative of -6 is 0
Now, we want to find x and y such that both `C_x` and `C_y` are 0:
This is a system of equations. We can solve it by multiplying the bottom equation by 2:
Subtracting, we get:
plugging this in (to either equation) we get:
So if `x=0` and `y=3`, then `C_x(x,y)=C_y(x,y)=0`
Posted by mlehuzzah on July 31, 2012 at 2:47 AM (Answer #1)
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