Give formula and name of the ester formed by ethanoic acid reacts with propanol;
(a) CH3CH2COOCH2CH3; ethyl propanoate
(b) CH3COOCH2CH2CH3; propyl ethanoate
(c) CH3COOCH2CH2CH3; ethyl propanoate
(d) none of the above
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Alcohols react with carboxylic acids to form esters. This reaction is catalyzed by acidic or basic conditions.
Esters have their own rules for naming.
The first part of the name comes from the alcohol, and it ends with the letters '-yl'.
The second part of the name comes from the carboxylic acid, and it ends with the letters '-oate'.
Here, propanol is the alcohol and ethanoic acid is the carboxylic acid.
So, ethanoic acid reacts with propanol to produce propyl ethanoate `(CH_3COOCH_2CH_2CH_3)` and water. The reaction is:
`CH_3COOH + CH_3CH_2CH_2OH = CH_3COOCH_2CH_2CH_3 + H_2O`
Therefore, option (b) `CH_3COOCH_2CH_2CH_3` ; propyl ethanoate is the correct answer.
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