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Give the equation of the asymptotes for the hyperbola x^2/36-y^2/4=1.
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We'll recall the equation of hyperbola:
x^2/a^2 - y^2/b^2 = 1
We'll recall the equation that gives the two asymptotes of hyperbola:
y = `+-` (b/a)*x
Comparing the given equation of hyperbola to the general equation, we'll identify a and b:
a = +6 or a = -6
b = +2 or b = -2
y = +(2/6)*x or y = -(2/6)*x
The equations of the two asymptotes of the given hyperbola are: y = x/3 and y = -x/3.
Posted by giorgiana1976 on July 26, 2011 at 6:10 PM (Answer #1)
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