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The general form of a quadratic with zeroes `alpha` and `beta` is...

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konkonz | (Level 1) Honors

Posted May 25, 2013 at 10:55 PM via web

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The general form of a quadratic with zeroes `alpha` and `beta` is `y=a(x-alpha)(x-beta)` . Find 'a' in terms of alpha and beta if the coefficient of x is a.

Also what does it mean by constant and coefficient?

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pramodpandey | College Teacher | (Level 3) Valedictorian

Posted May 26, 2013 at 4:00 AM (Answer #1)

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The zeros of polynomial

`y=a(x-alpha)(x-beta)` ,is same as roots of equation

`a(x-alpha)(x-beta)=0` .

The rlation between roots and coefficients are

`alpha+beta=(-coefficient of x)/(coefficient of x^2)`

`alpha beta= ( constant term)/( coefficient of x^2)`

In question  what is a ,

so answer `a!=0`

constant term = product of roots/ coefficient of x^2

in question it is `alpha beta` .

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