Gaseous hydrogen iodide is placed in a closed container at 425^0 C, Where it partially decomposes to hydrogen and iodine.
2HI(g)------->H_2(g) + I_2(g).
found theat [HI] = 3.53*10^-3M,[H_2] = 4.79*10^-4M, and [I_2] = 4.79*10^-4 M.What is the value of K_c at this temperature?
1 Answer | Add Yours
For a chemical reaction depicted by aA + bB <--> cC + dD, the equilibrium constant `K_c` is defined in terms of the concentration of the reactants and products by` K_c = ([C]^c*[D]^d)/([A]^a*[B]^b)` .
When gaseous hydrogen iodide is placed in a closed container at 425 C, the reaction that takes place is represented by the equation `2HI` (g)<-->`H_2` (g) + `I_2` (g), it is found that `[HI]` = 3.53*10^-3 M, [`H_2` ] = 4.79*10^-4 M, and [`I_2` ] = 4.79*10^-4 M.
The value of `K_c` in this case is `([H_2]*[I_2])/([HI]^2)`
The equilibrium constant is approximately 0.0184
We’ve answered 330,852 questions. We can answer yours, too.Ask a question