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g o f =? f(x)=(x-1)^2 and g(x)=x^1/2
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Finding g(f(x)) is the same as subtituting the f(x) function into the variable for g(x) and simplifying. In this case it involves taking the square root of the squared term, thereby cancelling the exponents:
g(f(x)) = [(x-1)^2]^1/2 = (x-1)^1 = x-1
g o f = x-1
Posted by ncchemist on May 24, 2011 at 7:03 AM (Answer #2)
We'll write the composition of the functions g and f as it follows:
gof(x) = g(f(x))
f(x) = (x-1)^2 and g(x) = sqrt x
We'll replace x by f(x), in the expresison of g(x).
g(f(x)) = g((x-1)^2)
g((x-1)^2) = sqrt [(x-1)^2]
g((x-1)^2) = |x-1|
The result of composition of the functions is:
(gof)(x) = g(f(x)) = |x-1|
Posted by giorgiana1976 on May 24, 2011 at 4:26 PM (Answer #3)
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