For the function y=(x-5)(x+2) please explain the following questions.

For the function y=(x-5)(x+2)

A.What are the x-intercepts?

B.What is the axis of symmetry?

C.What are the coordinates of the vertex?

D.Graph the function.

### 1 Answer | Add Yours

The function y=(x-5)(x+2) is that of a parabola.

y=(x-5)(x+2)

=> y = x^2 - 3x - 10

=> y = (x - 3/2)^2 - 49/4

The x-intercepts of the graph are the solution of the equation (x - 5)(x + 2) = 0 which gives x = 5 and x = -2.

The axis of symmetry is: x = 3/2

The vertex is (3/2, -49/4)

The graph of the function is given below with the axis shown in red.

### Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes