For the function y=(x-5)(x+2) please explain the following questions. For the function y=(x-5)(x+2)  A.What are the x-intercepts? B.What is the axis of symmetry? C.What are the coordinates of the...

For the function y=(x-5)(x+2) please explain the following questions. 

For the function y=(x-5)(x+2) 

A.What are the x-intercepts?

B.What is the axis of symmetry?

C.What are the coordinates of the vertex?

D.Graph the function.

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The function y=(x-5)(x+2) is that of a parabola.

y=(x-5)(x+2)

=> y = x^2 - 3x - 10

=> y = (x - 3/2)^2 - 49/4

The x-intercepts of the graph are the solution of the equation (x - 5)(x + 2) = 0 which gives x = 5 and x = -2.

The axis of symmetry is: x = 3/2

The vertex is (3/2, -49/4)

The graph of the function is given below with the axis shown in red.

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