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From a large consignment of apples, 400 apples were selected randomly and out of these...
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You need to use the following formula to evaluate the standard error of proportion, such that:
`SE = sqrt(p(1 - p)/n)`
You may evaluate p such that:
`p = 65/400 => p = 13/80 => p = 0.1625`
`1 - p = 1 - 0.1625 => 1 - p = 0.8375`
Replacing `0.1625` for `p,0.8375` for `1 - p` and 400 for n, yields:
`SE = sqrt(0.1625*0.8375/400) => SE = 0.018445443`
Hence, evaluating the standard error of proportion, under the given conditions, yields `SE = 0.018445443.`
Posted by sciencesolve on April 16, 2013 at 6:26 PM (Answer #1)
Also determine the range of proportion within which the population proportion would lie with 95% confidence.
Posted by guhadevdeep on April 16, 2013 at 6:31 PM (Answer #2)
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