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# A foam ball of mass 0.150 g carries a charge of -2.00 nC.  The ball is placed inside a...

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A foam ball of mass 0.150 g carries a charge of -2.00 nC.  The ball is placed inside a uniform electric field, and is suspended against the force of gravity.  What are the magnitude and direction of the electric field?

Posted by lkehoe on May 13, 2013 at 4:28 PM via web and tagged with charge, direction, force of gravity, magnitude, physics, science, uniform electric field

You need to evaluate the magnitude and direction of electric field, using Coulomb's force, such that:

`E = F/q`

Since the problem provides the mass of foam ball, you need to replace the product `m*g` for F, such that:

`E = (m*g)/q => E = (0.150*10^(-3)*9.8)/(-2*10^(-9))`

`E = -0.735*10^6N/C`

Hence, E needs to point vertically downward because `q = -2*10^(-9)<0` and its magnitude is of `E = 0.735*10^6N/C.`

Posted by sciencesolve on May 13, 2013 at 6:51 PM (Answer #1)

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