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A florist sold 2 types of flowers,roses and tulips.She kept a record of her...

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inquire123 | Student | eNoter

Posted June 17, 2013 at 12:30 AM via web

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A florist sold 2 types of flowers,roses and tulips.She kept a record of her sales.Unfortunately,she accidentally erased some information.Below shows what was left.Given that the cost of rose was 60% that of tulip,find the number of roses and tulips sold on Thursday.

Please solve it by forming simultaneous equation and the substitution/elimination method.Thanks

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted June 17, 2013 at 1:11 AM (Answer #1)

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First, look at the values given for Wednesday, these are used to determine the cost of the flowers. If the cost of tulips is X, the cost of a rose is X*0.6 or 90*X*0.6 + 60*X = 570 => X = 5

The cost of tulips is $5 and that of roses is $3.

On Thursday, the total number of flowers sold is 130 and the sales is $490.

If the number of roses sold is R, the number of tulips sold is 130 - R

Using the cost of flowers determined earlier, R*3 + (130 - R)*5 = 490

=> -2R = -160

=> R = 80

On Thursday, 80 roses and 50 tulips are sold.

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