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A cloud is at a potential 8.0x10^6 V relative to the ground. A charge of 40 C is...
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The energy dissipated in moving a charge Q between a potential difference V is equal to E = Q*V
Here the cloud is at a potential 8*10^6 V relative to the ground. A charge of 40 C is transferred in the lightning strike from the cloud to the ground.
The energy dissipated is equal to 8*10^6*40 = 3.2*10^8 J
Posted by justaguide on June 21, 2012 at 5:21 PM (Answer #1)
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