1 Answer | Add Yours
The energy dissipated in moving a charge Q between a potential difference V is equal to E = Q*V
Here the cloud is at a potential 8*10^6 V relative to the ground. A charge of 40 C is transferred in the lightning strike from the cloud to the ground.
The energy dissipated is equal to 8*10^6*40 = 3.2*10^8 J
We’ve answered 317,831 questions. We can answer yours, too.Ask a question