# Find the zero of the polynomial P(x) = 3x^3 + 3x^2 -12x - 12

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The zeros of the polynomial 3x^3 + 3x^2 -12x - 12 are the solution of the equation 3x^3 + 3x^2 -12x - 12 = 0

3x^3 + 3x^2 -12x - 12 = 0

=> 3x^2(x + 1) - 12(x + 1) = 0

=> (3x^2 - 12)(x + 1) = 0

x + 1 = 0

=> x = -1

3x^2 - 12 = 0

=> x^2 = 12/3 = 4

=> x = 2 and x = -2

**The zeros of the polynomial 3x^3 + 3x^2 -12x - 12 are 1, 2 and -2**