Better Students Ask More Questions.
Find `y=f(f^(-1)(3x))` in the form of y=ax/(bx + c), where a,b and c are real...
2 Answers | add yours
`f(x) = 2log_e(x+1)` and
`f^(-1)(x) = e^(x/2)-1`
To work out
`y = f(f^(-1)(3x))`
however, we don't need either of these as, since `f^(-1)(x)`is the inverse of `f(x)`,
`f(f^(-1)(3x))` is simply `3x`.
We can write `y = f(f^(-1)(3x))` in the form `(ax)/(bx+c)` where
`a = 3`, `b = 0` and `c=1`
y = 3x/(0x + 1)
Posted by mathsworkmusic on April 17, 2013 at 11:40 AM (Answer #2)
Join to answer this question
Join a community of thousands of dedicated teachers and students.