find y' and evaluate y' at indicated point  Given ln y = 2x^2 -x ; at (2,1)

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You need to evaluate y', hence, you should differentiate the function with respect to x such that:

`(1/y)*y' = 4x - 1`

`y' = (4x - 1)*y`

You need to evaluate y' at the point (2,1) such that:

`y' = (4*2 - 1)*1`

`y' = 7`

Hence, evaluating y' for `ln y = 2x^2 -x` , at the point (2,1), yields `y' = 7` .

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