# find the x-intercept and the y-intercept for the graph of the equation 2x+2y=-6

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Since this equation is in standard form we can answer this by allowing both x and y to equal zero, one at a time. Starting with x=0 we get the equation

0x+2y=-6 or 2y=-6

divide both sides of the equation by 2 and we get

y=-3 so the coordinates of the y intercept will be (0,-3)

Now start with the original equation again, and let y=0 and we get

2x+0y=-6 or 2x=-6

divide both sides of the equation by 2 (the x coefficient) to get x=-3 and the coordinates of the x intercept will be (-3,0)

Therefore, the x and y intercepts of the equation 2x+2y=-6 are (-3,0) and (0,-3)

2x+2y=-6

To find where the function intersect with the x-axis, then we need to substitute with x=0

2(0) +2y =-6

==> 2y = -6\

==> y=-3 or he function intersect with x-axis at the point (0,-3)

Now to find out where the function intersect with y-axis, then y will be 0:

2x+ 2(0) =-6

==> x= -3 (the function intersect with y=axis at the point (-3,0)

To find the x and y intercept for the graph of 2x+2y = -6.

Solution:

The intercept of a graph and x axis is got by finding the intersection point on the x axis by putting y= 0 in the equation of the graph and then solving for x. Similarly, by putting x=0 in equation of the graph and solving for y,we get the y intercept.

2x+2(0) = -6 gives 2x = -6 implies x = -6/2 = -3.

So -3 is the x intercept.

2(0)+2y = -6 implies 2y = -6. y = -6/2 = -3.Therefore -3 is the y intercept.

To find the intercepts of a graph with an axis , we have to calculate f(x)=0 and f(0).

When calculating f(x)=0, we'll find the interception of the graph with x axis.

We'll re-write the given equation:

2x+2y=-6

We'll isolate the term in y, to the left side:

2y = -6-2x

We'll divide by 2:

y = -3 - x

Now, we'll calculate f(x)=0, that means that y=0.

0 = -3 - x

We'll move x to the left side:

x = -3

The interception point of the graph with x axis is: (-3,0).

Now, we'll calculate the interception point with y axis and for this reason, we'll put x=0.

y = -3 - 0

y = -3

The interception point of the graph with y axis is: (0,-3).

2(0)+2y=-6

2y=-6

2y/2=-6/2

y=-3

2x+2(0)=-6

2x=-6

2x/2=-6/2

x=-3

y-intercept=-3 and x-intercept= -3

find the x-intercept and the y-intercept for the graph of the equation 2x+2y=-6

to find the x-intercept solve for x and to find the y intercept solve for y

x intercept (y=0)

2x + 2(0) = -6

2x = -6

divide by 2 to get rid of the 2 in front of the x

`(2x)/2 = -6/2 `

x= -3

x intercept = -3,0

y intercept (x=0)

2(0)+2y=-6

2y = -6

just like last time divide by 2 to get y alone

2y / 2 = -6/2

y=-3

y intercept = 0,-3