# Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x) =-(x+8)^2-3

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Yes. If a < 0 then the parabola goes downward (sad). The vertex (-8, -3) is in the third quadrant, so the parabola starts in the 3rd quadrant and goes downward.

If the formula for a parabola is in vertext form

y = a(x - b)^2 + c

x = b is the line of symmetry, (b, c) is the vertex, and if a > 0 then the vertex is the minimum, else if a < 0 then the vertex is the maximum.

The equation is in vertex form, so the axis of symetry is at

x = -8

The vertex is at (-8, -3)

-3 is the maximum.

when you graph. would the graph be in quadrant 3 and going down then?