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find the vertex of `f(x)= - 4/7(x-6)^2+1` .  

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find the vertex of `f(x)= - 4/7(x-6)^2+1` .

 

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Posted (Answer #1)

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`f(x)= - 4/7(x-6)^2+1`

We know that` (x-6)^2` is always positive or zero. Then `- 4/7(x-6)^2+1` is always negative or zero. So f(x) will have a maximum value. Maximum occurs when` - 4/7(x-6)^2` is maximum. Because of `-4/7` term the maximum that `- 4/7(x-6)^2` is 0. This comes when x = 6.

When x = 6 then f(x) = f(6) = 1.

So the vertex is (6,1).

 

As we described earlier f(x) will have a maximum. Graph is shown below.

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