1 Answer | Add Yours
`(ln|x|)/|x| > (ln|x|)/x`
First, let's think about the graph of ln|x| (my graph plugin isn't behaving, so graph it yourself if you need to). The function is positive when x < -1 and also when x > 1, but negative when x is between -1 and 1 (not including -1, 0, and 1).
So let's think of x < -1. Then the inequality is true, since the left side is positive and the right side is negative.
When x = -1, both sides have 0 on the numerator, so they're equal (inequality is false).
How about x between -1 and 0? Left side is negative, right side is positive, so false.
When x = 0, both sides are undefined (false).
When x > 0, the absolute values don't matter, so both sides are equal.
Therefore, answer is x < -1.
We’ve answered 317,385 questions. We can answer yours, too.Ask a question