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You should come up with the following notation for the three consecutive even integers, such that:
`n, n+2, n+4`
The problem provides an information that relates the integers, such that:
`(n+2)(n+4) = 20 + 10n`
`n^2 + 4n + 2n + 8 - 10n - 20 = 0 => n^2 - 4n - 12 = 0`
Using quadratic formula yields:
`n_(1,2) = (4+-sqrt(16 + 48))/2`
`n_(1,2) = (4+-sqrt64)/2 => n_(1,2) = (4+-8)/2`
`n_1 = 6; n_2 = -2`
Since the problem provides the information that the integers are positive, hence, only `n = 6` fulfills the condition.
Hence, evaluating the three consecutive even positive integers, yields 6, 8, 10.
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