Find the sum of each of the following infinite series. If a series does not have a sum, write no sum as the answer. 1/2+1+2+4... 9-3+1-1/3+1/9...



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Posted on (Answer #1)

First series is geometric series with ratio `r=2` and geometric series is convergent only if `|r|<1`, hence the first series isn't convergent. In other words sum of the first series is `oo.`

The other series we can look as the sum of two geometric series. One with general term `a_n=(1/9)^(n-2)` and other with general term `b_n=-(1/3)^(n-2),` `n=1,2,3,ldots`

Hence sum of your series is

`S=sum_(n=1)^ooa_n+sum_(n=1)^oob_n`                                                      (1)

Sum of infinite geometric series is calculated by formula

`sum_(n=1)^ooa_1r^n=(a_1)/(1-r)`` `

Hence we have



Now we put that into (1) to get

`S=81/8-9/2=(81-36)/8=45/8` <-- Your solution

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