Better Students Ask More Questions.
Find the slope of the tangent line to y=x^5-3x^-3 at x=-2
1 Answer | add yours
The slope of a tangent line to a curve at any point is the value of the first derivative at that point.
The function we have is y = x^5 - 3x^(-3)
y' = 5x^4 - (-3*3)x^(-4)
=> y' = 5x^4 + 9x^-4
At x = -2
y' = 5*(-2)^4 + 9*(-2)^(-4)
=> 5*16 + 9/ 16
The slope of the tangent to the curve y=x^5-3x^-3 at x=-2 is 1289/16
Posted by justaguide on May 3, 2011 at 11:33 PM (Answer #1)
Join to answer this question
Join a community of thousands of dedicated teachers and students.