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Find the slope of the tangent to the curve: f(x)=x^3-x^2-x+1 at x= -2Show all work.
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(Level 1) Associate Educator, Expert, Newton
The slope of the tangent line of `f(x)` at `a` is `f'(a)`
That is, you find the derivaive of `f` and then plug in `a`
`f'(-2) = 3(-2)^2-2(-2)-1=15`
So the slope of the tangent line of f at -2 is 15.
Posted by mlehuzzah on August 18, 2012 at 10:32 PM (Answer #1)
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