# Find the slope of the secant line passing through (−3, f(−3)), (2, f(2)) when f(x)=x^2−3x+2.

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The slope of the secant line is the slope of the line from `(-3,f(-3))` to `(2,f(2))` . We can evaluate:

`f(-3)=(-3)^2-3(-3)+2`

`=9+9+2`

`=20`

`f(2)=2^2-3(2)+2`

`=4-6+2`

`=0`

So the slope between those two points is

`m={0-20}/{2-(-3)}`

`=-20/5`

`=-4`

**The slope of the secant line is -4.**

slope m will be: -4