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Find the slope ‐ intercept equation of the line with the following properties:...

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pelitos03 | Student, Undergraduate | eNotes Newbie

Posted October 6, 2012 at 8:19 PM via web

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Find the slope ‐ intercept equation of the line with the following properties:

Perpendicular to the line x - 4y = 2 containing the point (5,2)

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted October 7, 2012 at 2:00 AM (Answer #1)

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The required line is perpendicular to the line x - 4y = 2. This is the case when the product of the slope of the line and that of x - 4y = 2 is equal to -1.

x - 4y = 2 can be written as y = x/4 - 2/4 in slope intercept form. The slope of the required line is -4.

As it has the point (5, 2) its equation is:

(y - 2)/(x - 5) = -4

=> y - 2 = -4x + 20

=> y = -4x + 22

The equation of the required line in slope-intercept form is y = -4x + 22

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jishnudeepkar | Student, Grade 11 | (Level 1) Honors

Posted October 7, 2012 at 1:48 AM (Answer #2)

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its simple

the slope of reqd line will be -4. and contains the pt (5,2)

(y-2)= -4(x- 5)

y+4x=22    divide by 22

y/22 + x/5.5= 1

     

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Wiggin42 | Student, Grade 11 | (Level 2) Valedictorian

Posted April 27, 2014 at 12:28 AM (Answer #3)

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Perpendicular to the line x - 4y = 2 containing the point (5,2)

Lets take your standard form equation and change it to slope-intercept to readily identify the slope: 

4y = x - 2

y = (1/4)x  - (1/2)

The slope is 1/4. 

A perpendicular line's slope will be the negative reciprocal of this one so -4. 

Now we have a point and a slope, lets first write out the perpendicular line in point-slope form. 

y - 2 = -4(x - 5)

Distribute the -4 and solve for y to put this into slope-intercept form. 

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