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Find the slope ‐ intercept equation of the line with the following properties:...
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The required line is perpendicular to the line x - 4y = 2. This is the case when the product of the slope of the line and that of x - 4y = 2 is equal to -1.
x - 4y = 2 can be written as y = x/4 - 2/4 in slope intercept form. The slope of the required line is -4.
As it has the point (5, 2) its equation is:
(y - 2)/(x - 5) = -4
=> y - 2 = -4x + 20
=> y = -4x + 22
The equation of the required line in slope-intercept form is y = -4x + 22
Posted by justaguide on October 7, 2012 at 2:00 AM (Answer #1)
the slope of reqd line will be -4. and contains the pt (5,2)
(y-2)= -4(x- 5)
y+4x=22 divide by 22
y/22 + x/5.5= 1
Posted by jishnudeepkar on October 7, 2012 at 1:48 AM (Answer #2)
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