Find the probability that a point chosen at random in the figure lies in the shaded region.  http://www.flickr.com/photos/93084714@N07/8619998387/in/photostream

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pramodpandey | College Teacher | (Level 3) Valedictorian

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Total area= pi.r^2 Area of shade region= pi.r^2- pi. (r/2)^2 =(3.pi)(r^2)/4 Area of favourable for the event E= (3/4)pi.r^2 Area of non favourable event =(1/4) pi.r^2 P(E)= favourable area/ total area = {(3/4)pi.r^2}/{pi.r^2} = (3/4)

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