# Find the points where the line y = 2x+3 meets the line 2y-x+3 = 0

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Given the lines:

y= 2x+3................(1)

2y-x + 3 = 0............(2)

We need to find the points of interception.

We will substitute (1) into (2).

==> 2(2x+3) - x + 3 = 0

==> 4x + 6 -x + 3 = 0

==> 3x = -9

==> x = -3

==> y= 2x+3 = 2*-3+3 = -3

**Then, the point of interception is (-3, -3).**

To find the point where the two lines meet we have to solve

y = 2x+3 ...(1)

2y-x+3 = 0 ...(2)

substitute y = 2x + 3 from (1) in (2)

2(2x + 3) - x + 3 = 0

=> 4x + 6 - x + 3 = 0

=> 3x + 9 = 0

=> x = -3

y = 2*(-3) + 3

=> -6 + 3

=> -3

**The point of intersection of the two lines is (-3 , -3)**