# Find the numbers such that their sum is 23 and the difference is 1

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Let the numbers be x and y :

Given that the sum of the numbers is 23

Then we will wrtie:

x + y = 23............(1)

Also, given the difference between the numbers is 1:

Then we will write:

x - y = 1...................(2)

Now using the elimination method, we will solve the system.

let us add (1) and (2):

==> 2x = 24

Now divide bu 2:

**==> x = 12**

Now to find y , we will substitue in (2):

x - y = 1

12 - y = 1

**==> y= 11**

**Then the answer is :**

**The numbers are 11 and 12.**

**The sum : 11+ 12 = 23**

**The difference : 12-11 = 1**

The sum of the numbers is 23 and their difference is 1.

Since the difference of the two numbers is 1 , one of the numbers is more than the other number by 1.

So we keep one separate out of the sum 23 and the remaining 22 we can equally divide.

Therefore 23-1 = 2. 22/2 = 11.

Now the two numbers are 11 and 11.

Now we add the 1 to one of the 11. Then we get 12.

So the two numbers are 11 and 12 whose sum is 11+12 = 23 and the difference between 11 and 12 is 1.