Better Students Ask More Questions.
Find numbers a, b, and c so that the graph of `f(x) = a(x)^(2)+b(x)+c` has x-intercepts...
1 Answer | add yours
Substitute x=0 and y=0 in`f(x)=y=ax^2+bx+c` (1)
Substitute x=8 and y=0 and c=0:
The equation of the tangent is:
Substitute 2 for x in (3):
Subsstitute y=32+b in (1):
Substitute (2) in (4):
Substitue 16 for b in (2):
Thus the function is:`f(x)=-2x^2+16x`
Posted by flbyrne on September 12, 2013 at 2:27 AM (Answer #1)
Join to answer this question
Join a community of thousands of dedicated teachers and students.