Find the lengths of each of the following right triangles.
In triangle A, the longer leg is 4 more than the shorter leg and the hypotenuse is 4 more than the longer leg.
I think the short leg=12, the long leg =16 and the hypotenuse=20
Is this right?
In triangle B, the short leg =x the long leg =1/2x+11 and the hypotenuse=2x+1
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For triangle A:
Let l = the longer arm
Let s = the shorter arm
Let h= the hypotenuse
We are given that: `l=4+s ` and `h=4+l`
And we also know that: `h^2=l^2+s^2`
Rearrange the given equations to be a function of l:
`s=l-4 ` and `h=4+l`
Substitute into the Pythagorean equation:
Therefore, your answers for triangle A are correct :)
For triangle B:
Let x = the short leg
Let l = the long leg = `1/2x+11`
Let h = the hypotenuse = `2x+1`
We know that:
a=11; b=-28; c=-480
Since the length of a side cannot be negative,` x=x_1=4` :
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