find the least number which becomes divisible by 7,11 and 13 when 4000 is subtracted from it.
2 Answers | Add Yours
Since 7, 11 and 13 are prim numbers the least number divisible by all of them is their product, that is
Now we add 4000 and your result is 5001.
If you subtract 4000 from 5001 you get 1001 which is the smallest natural number divisible by 7, 11 and 13.
Alternatively you cloud use congruences.
The number you are searching for is `5001`
Join to answer this question
Join a community of thousands of dedicated teachers and students.Join eNotes