find the integral x(4x + 11)^2 dx  = ____________ + c

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jeew-m | College Teacher | (Level 1) Educator Emeritus

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`intx(4x+11)^2dx`

`= intx(16x^2+88x+121)dx`

`= int(16x^3+88x^2+121x)dx`

`= (16x^4)/4+(88x^3)/3+(121x^2)/2+C`

`= 4x^4+(88x^3)/3+(121x^2)/2+C`

 

So the answer is;

`= 4x^4+(88x^3)/3+(121x^2)/2+C`

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