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Find how many four digit numbers can be formed by seven digits 1,2,4,5,6,8 and 9 if any...
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Number of ways to select 1st digit = 7
Number of ways to select 2nd digit = 6
Number of ways to select 3rd digit = 5
Number of ways to select 4th digit = 4
So with out repetition number of 4-digit numbers that can be formed are `7xx6xx5xx4 = 840` .
We have 3 odd number and 4 even number in the set.
Ways to select two odds `= ^3C_2 = 3`
Ways to select two even `= ^4C_2 = 6`
Number of 4-digit numbers with two even and two odd `3xx6 = 18`
But we can rearrange these four digits within the number.
So total number of ways `= 18xx4! = 432`
So we can form 432 four digit numbers for the given condition.
Posted by jeew-m on July 10, 2013 at 8:56 PM (Answer #1)
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