Find g[f(x)] if f(x) =`sqrt(x^2 -2)and g(x) = x^2 + 2`

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`g(f(x))=x^2+2`

`g(f(x))=(f(x))^2+2`

Since `f(x)=sqrt(x^2-2)` , then

`g(f(x))=(sqrt(x^2-2))^2+2`

`g(f(x))=x^2-2+2`

`g(f(x))=x^2` **Hence, `g(f(x))=x^2 ` .**

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