# find the exact value in degrees: A. y=arcsin(1/2) B. y=arctan(-sqrt3)

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y = arc sin (1/2)

=> y = 30 degrees

**The required solution is 30 degrees.**

We know that sin y = 1/2, so that arcsin (1/2) = y

y = 30 degrees

We also know that tan y = -sqrt 3 => arctan (-sqrt 3) = y

The tangent is negative in the 2nd and the 4th quadrants.

If the angley is in the 2nd quadrant, the angle y, for arctan (-sqrt 3) = y, is y = 180 - 60 = 120 degrees.

If the angle x is in the 4th quadrant, then x = 360 - 60 = 300 degrees.

**The angle y for arcsin (1/2) = y is y = 30 degrees and the angle y for arctan (-sqrt 3) = y, are 120 degrees or 300 degrees.**