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find the equation of the tangent to the parabola x=2at, y=at^2 the point where t=3
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convert equation in cartesian form ,we have
`t^2=x^2/(4a^2)` ,substitute in y
differentiate (i) with respect to x,
Equation of the tangents at 't'
Posted by pramodpandey on April 6, 2013 at 6:08 AM (Answer #1)
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