# Find the equation of the line that passes through (4, 3) and is parallel to the line 3x-y =7

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Use the point-slope equation. We know that it must have a slope of 3 because it is parallel to the line y = 3x - 7.

y - y1 = m(x - x1)

y - 3 = 3(x - 4)

y = 3(x - 4) + 3

y = 3x - 12 + 3

y = 3x - 9

The line equation is:

y-y1= m(x-x1) where (x1,y1) is any point passes through the line and (m) is the slope.

Since the line is parallel to 3x-y=7 , then they have the same slope.

3x-y=7

==> y= 3x-7

Then the slope (m) =3

We have the point (4,3) passes through the line:

y-3= 3(x-4)

==> y= 3x -12 +3

==> y= 3x -9