Find the equation of the line tangent to the graph of f(x)=(2x-5)/(x+1) at the point where x=0
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The equation of the line to the curve represented by `y = (2x - 5)/(x+1)` has to be determined at the point where x = 0.
The slope of the tangent to the curve y at any point is the value of y' at that point.
y = `(2x - 5)/(x+1)`
=> `y' = 7/(x+1)^2`
at x = 0, y' = 7.
Also at x = 0, y = -5
The equation of the tangent is `(y + 5)/(x - 0) = 7`
=> y + 5 = 7x
=> 7x - y - 5 = 0
The required equation of the tangent is 7x - y - 5 = 0
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