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Find the equation of the line (in slope intercept form) through (-5,8) and...

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user6760353 | Student, Undergraduate | (Level 1) Honors

Posted September 22, 2013 at 9:43 PM via web

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Find the equation of the line (in slope intercept form) through (-5,8) and perpendicular to the line 4x + 2y = 8

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tjbrewer | Elementary School Teacher | (Level 2) Associate Educator

Posted September 22, 2013 at 9:55 PM (Answer #1)

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We re-write the equation in slope-intercept form to find the slope of the ``equation.  `4x+2y=8` We subtract 4x from each side and get `2y=8-4x=-4x+8` We divide both sides by 2 and its `y=-2x+4`

The equation we seek is perpendicular to this so its slope should be the negative reciprocal of -2, which is `1/2`

Now that we know the slope(m), we can find the intercept (b) by inserting the ordered pair (-5,8) into the equation y=mx+b

`y=mx+b->8=1/2(-5)+b=-2 1/2+b` We add `2 1/2` to each side and we get `10 1/2=b`

The equation in slope intercept form is `y=1/2 x+10 1/2`

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