# find the equation of a line prependicular to y=-2 passing through (-3, 1)equation of a line given the slope and a point

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We will write the equation of the line into the standard form.

==> y-y1 = m (x-x1) where (x1,y1) is any point passes through the line and m is the slope.

==> Given the points ( -3,1) passes through the line.

==> L1: y -1 = m (x+ 3)

Now given that the line is perpendicular to the line y= -2.

But the line y= -2 is parallel to the x-axis.

Then the line L1 is parallel to the y-axis.

Then the slope is given by m = 1/0

==> L1: y- 1 = 1/0 ( x+3)

==> L1: x = -3

**Then, the equation of the line is x= -3**

find the equation of a line prependicular to y=-2 passing through (-3, 1)

equation of a line given the slope and a point

First, realize that y = -2 is a horizontal line. It has a slope of 0. Perpendicular lines have a slope that is the negative reciprocal. The negative reciprocal of 0 is undefined since -1/0 is undefined. Lines with undefined slopes are vertical lines. You need a vertical line that passes through (-3, 1). In a vertical line, all y values share the same x value. So you're perpendicular line must be x = -3.